1+2+3+4+5······+100+101=几

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1+2+3+4+5······+100+101=几

1+2+3+4+5······+100+101=几
1+2+3+4+5······+100+101=几

1+2+3+4+5······+100+101=几
[(1+101)×101]÷2

5151

=n(1+n)/2

5101

301

(1+101)×50÷2

5151,望采纳,谢谢

5151

(1+101)×101÷2=

5151

5151

5151

利用梯形公式(1+101)X101X1/2=5105

5151.(1+101)×101÷2

102.50=5100

简单,等于5151

答案:5151(高中有等差数列前n项和Sn=n(a1+an)/2)(小学有(首项+尾项)×项数/2)

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