曲线y=(1/5)x^5+3x^2+4x在x=1处的切线的倾斜角是

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 00:46:57
曲线y=(1/5)x^5+3x^2+4x在x=1处的切线的倾斜角是

曲线y=(1/5)x^5+3x^2+4x在x=1处的切线的倾斜角是
曲线y=(1/5)x^5+3x^2+4x在x=1处的切线的倾斜角是

曲线y=(1/5)x^5+3x^2+4x在x=1处的切线的倾斜角是
y=(1/5)x^5+3x^2+4x
y'=x^4+6x+4
x=1时,y'=1+6+4=11
倾斜角为arctan11