5 设数列{an}的前n项和为Sn,a1=1,a2=2,且a(n+2)=an+3(n=1,2,3……),则S100=

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/08 04:19:55
5 设数列{an}的前n项和为Sn,a1=1,a2=2,且a(n+2)=an+3(n=1,2,3……),则S100=

5 设数列{an}的前n项和为Sn,a1=1,a2=2,且a(n+2)=an+3(n=1,2,3……),则S100=
5 设数列{an}的前n项和为Sn,a1=1,a2=2,且a(n+2)=an+3(n=1,2,3……),则S100=

5 设数列{an}的前n项和为Sn,a1=1,a2=2,且a(n+2)=an+3(n=1,2,3……),则S100=
∵a[n+2]=a[n]+3 (n=1,2,3,...)
∴a[n+2]-a[n]=3
当n=2k-1(k=1,2,3,...),即n是奇数时:
∵a1=1
∴{a[2k-1]}是首项为1公差为3的等差数列
其通项公式是:a[m]=1+3(m-1)=3m-2
其前 m项和是:D[m]=m(1+3m-2)/2=m(3m-1)/2
∵项数m=(尾数-首数)/2+1=(n-1)/2+1=(n+1)/2
∴D[n]=(n+1)/2*[3(n+1)/2-1]/2=(n+1)(3n+1)/8
当n=2k(k=1,2,3,...),即n是偶数时:
∵a2=2
∴{a[2k]}是首项为2公差为3的等差数列
其通项公式是:a[m]=2+3(m-1)=3m-1
其前 m项和是:E[m]=m(2+3m-1)/2=m(3m+1)/2
∵项数m=(尾数-首数)/2+1=(n-2)/2+1=n/2
∴E[n]=n/2*(3n/2+1)/2=n(3n+2)/8
∴S[100]=D[99]+E[100]=3725+3775=7500

a(n+2)=an+3
当n=1时 a3=a1+3=4
a1=1 a2=2 a3=4 可以看出为等比数列 公比为2
求和公式
Sn=a1(1-q^n)/(1-q) =(a1-an*q)/(1-q) (q≠1)
s100=1*(1-2^100)/(1-2)
=2^100-1

数列{an},中,a1=1/3,设Sn为数列{an}的前n项和,Sn=n(2n-1)an 求Sn 设数列an的首项a1等于1,前n项和为sn,sn+1=2n设数列an的首项a1等于1,前n项和为sn,sn+1=2n 设数列{an}的前n项和为Sn,a1=10,a(n+1)=9Sn+10 设数列An的前n项和为Sn,已知a1=1,An+1=Sn+3n+1求证数列{An+3}是等比数列 设数列an的前n项和为Sn,满足2Sn=an-2∧n+1 +1 ,且a1,a2+5,a3成等差设数列an的前n项和为Sn,满足2Sn=an-2∧n+1 +1 ,且a1,a2+5,a3成等差数列.求a1,an的通项 设数列【An】的前n项和为Sn,A1=10,An+1=9Sn+10.设Bn=lgAn,求证数列【Bn】为等差数列 设数列{an}的前n项和为Sn,若a1=1,Sn=2an+Sn+(n∈N+),则a6= 强大的数学题:设数列{An}的前N项和为Sn已知A1=.设数列{An}的前N项和为Sn,已知A1=1,A2=6,A3=11,且(5n-8)Sn+1 - (5n+2)Sn = -20n-8 (n=1,2,3,4,.)请证明数列{An}为等差数列 设数列An的前n项和为Sn,且a1=1,An+1=1/3Sn,求数列an的通项公式. 设数列an的前n项和为Sn,已知a1=1,3an+1=Sn,求数列an的通项公式 设数列an的前n项和为Sn,已知a1=1,3an+1=Sn,求数列an的通项公式 设Sn为数列an的前n项和,Sn=kn*2+n,n∈N*,其中k为常数,求a1,an 数列an的前n项和为Sn,a1=1,an+1=2Sn 设bn=log3an,求数列bn的前n项和Tn数列an的前n项和为Sn,a1=1,an+1=2Sn 设bn=log3an,求数列bn的前n项和Tn 设数列an的前n项和为Sn,且2an=Sn+2n+1 求a1 a2 a3 求证:数列{an+2}是等比数列 求数列{n*an}的前n项和Tn 设数列an的前n项和为Sn,且2an=Sn+2n+1 求a1 a2 a3 求证:数列{an+2}是等比数列 求数列{n*an}的前n项和Tn 设数列{an}的前n项和为sn,sn=a1(3^n-2)/2(n≥1),a4=54,则a1= 设数列{an}的前n项和为Sn,数列{Sn}的前n项和为Tn,满足Tn=2Sn-n^2,n∈N*.求a1的值以及an的通项公式. 设数列{an}的前n项和为Sn,已知首项a1=3,且Sn+1+Sn=2an+1,试求此数列的通项公式an及前n项和Sn