1.2 0.3 0.4 0.5 6.7 01.2 0.3 0.4 0.5 6.7 0.8 0.9＝10空的地方填＋－求机智的小伙伴们指点

1.2 0.3 0.4 0.5 6.7 01.2 0.3 0.4 0.5 6.7 0.8 0.9＝10空的地方填＋－求机智的小伙伴们指点 0.3与0.5之间只有小数0.4. 0.3x+0.65=0.4x+0.5 比较大小0.2^0.5 0.4^0.3 0.4y+0.9/0.5-0.3+0.2y/0.3=1 解方程.（x-0.3)=0.5*1.2 （+1.2）+（-0.4）+（+1）+（0）+（-1.1）+（-0.5）+（+0.3）+（0.5）+（-0.6）+（-0.9）=? 0.4y+0.9/0.5 - 0.3-0.2y/0.3=1(0.4y+0.9)/0.5 - (0.3-0.2y)/0.3=1 C语言二维数组的一点疑问!const float rain[YEARS][MONTHS]={4.3,4.3,4.3,3.0,2.0,1.2,0.2,0.2,0.4,2.4,3.5,6.6,8.5,8.2,1.2,1.6,2.4,0.0,5.2,0.9,0.3,0.9,1.4,7.3,9.1,8.5,6.7,4.3,2.1,0.8,0.2,0.2,1.1,2.3,6.1,8.4,7.2,9.9,8.4,3.3,1.2,0.8,0.4,0.0,0.6,1. 4.8×0.25= 0.78×98＝ 0.5×2.33×8= 1.5×105= 0.3×2.5×04.8×0.25=0.78×98＝0.5×2.33×8=1.5×105=0.3×2.5×0.4＝1.2×2.5+0.8×2.5＝列竖式简便 有一些已知的数据如a,b,c,d,e,f.和已知的一些数字如0.2 ,0.3 ,0.4 ,0.5 想求得一个X 使得a/x ,b/x ,c/x,d/x.的得数为0.2 ,0.3,0.4 0.5或者1.2 ,1.3 ,1.4 .2.2,2.3,2.4..3.2,3.3,3.4..n+0.2,n+0.3,n+0.4..我不知道能不能得出一 怎样使用matlab,利用最小二乘法得到回归方程影响结果的变量分别为x1,x2,x3,结果变量为y.x1=[0.4,0.4,0.4,0.4,0.2,0.2,0.2,0.2,0.4,0.4,0.4,0.4,0.2,0.2,0.2,0.2,0.3,0.3,0.1,0.5,0.3,0.3,0.3,0.3,0.3,0.3,0.3,0.3,0.3,0.3,0.3];x2=[0.0 在括号里填运算符号0.1( )0.2( )0.3( )0.4( )0.5=30.1( )0.2( )0.3( )0.4( )0.5=40.1( )0.2( )0.3( )0.4( )0.5=5 (0.38+x)/0.3-0.4=1.2 解方程! (0.1*0.3*0.9+0.2*0.6*1.8+0.3*0.9*2.9)除以（0.1*0.2*0.4+0.2*0.4*0.8+0.3*0.6*1.2） (0.1*0.3*0.9+0.2*0.6*1.8+0.3*0.9*2.9)除以（0.1*0.2*0.4+0.2*0.4*0.8+0.3*0.6*1.2） 解方程0.3x+0.8/0.5-0.02x+0.3/0.3-1=0.8x-0.4/3 6.7×0.3列竖式