若(3xy+2)^2+|7-x-y|=0,求代数式(5xy+10y)-[-5x-(4xy-2y+3x)]的值

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若(3xy+2)^2+|7-x-y|=0,求代数式(5xy+10y)-[-5x-(4xy-2y+3x)]的值
若(3xy+2)^2+|7-x-y|=0,求代数式(5xy+10y)-[-5x-(4xy-2y+3x)]的值

若(3xy+2)^2+|7-x-y|=0,求代数式(5xy+10y)-[-5x-(4xy-2y+3x)]的值
(3xy+2)^2+|7-x-y|=0,则 3xy+2=0,7-x-y=0,即 x+y=7,xy= -2/3
(5xy+10y)-[-5x-(4xy-2y+3x)]
=5xy+10y-(-5x-4xy+2y-3x)
=5xy+10y+5x+4xy-2y+3x
=9xy+8x+8y
=9xy+8(x+y)
= 9*(-2/3)+8*7
= -6+56
= 50

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根据题意得：
3XY+2=0
7-X-Y=0
∴XY=--2/3，X+Y=7，
原式=5XY+10Y-［-5X-4XY+2Y-3X)］
=5XY+10Y+8X+4XY-2Y
=9XY+8(X+Y)
=-6+56
=50。

(3xy+2)^2+|7-x-y|=0
∴3xy+2=0
7-x-y=0
∴x+y=7
xy=-2/3
(5xy+10y)-[-5x-(4xy-2y+3x)]
=5xy+10y-(-5x-4xy+2y-3x)
=5xy+10y+5x+4xy-2y+3x
=9xy+8y+8x
=9xy+8(x+y)
=9×(-2/3)+8×7
=50

一个数的平方与绝对值均为非负数，和为0只有分别等于0

3xy+2=0 3xy=-2
7-x-y=0 x+y=7
(5xy+10y)-[-5x-(4xy-2y+3x)]=5xy+10y-[-5x-4xy+2y-3x]

=5xy+10y+5x+4xy-2y+3x
=9xy+8x+8y
=3×3xy+8(x+y)
=3×（-2）+8×7
=-6+56
=50

∵(3xy+2)^2+|7-x-y|=0,
∴3xy+2=0，7-X-Y=0
∴3XY=-2，X+Y=7
(5xy+10y)-[-5x-(4xy-2y+3x)]
= 5xy+10y+5x+4xy-2y+3x
=9xy+8y+8x
=3·3XY+8(X+Y)
∴3·3XY+8(X+Y)=3×(-2)+8×7=50

由(3xy+2)^2+|7-x-y|=0，(3xy+2)^2>=0，|7-x-y|>=0，
所以3xy+2=0，7-x-y=0，即xy=-2/3，x+y=7
(5xy+10y)-[-5x-(4xy-2y+3x)]
=5xy+10y+5x+(4xy-2y+3x)
=5xy+10y+5x+4xy-2y+3x
=9xy+8y+8x
=9xy+8(x+y)
=9*(-2/3)+8*7
=-6+56
=50
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