(lg3/2lg2+lg3/3lg2)*(lg2/lg3+lg2/2lg3)

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(lg3/2lg2+lg3/3lg2)*(lg2/lg3+lg2/2lg3)

(lg3/2lg2+lg3/3lg2)*(lg2/lg3+lg2/2lg3)
(lg3/2lg2+lg3/3lg2)*(lg2/lg3+lg2/2lg3)

(lg3/2lg2+lg3/3lg2)*(lg2/lg3+lg2/2lg3)
(lg3/2lg2+lg3/3lg2)*(lg2/lg3+lg2/2lg3)
=【log(4)3+log(8)3】*【log(3)2+log(9)2】
=【1/2log(2)3+1/3log(2)3】*【log(3)2+log(9)2】
=【5/6log(2)3】*【3/2log(3)2】
=5/6log(2)3*log(3)2
=5/6
应该是利用换底公式和运算公式吧
我刚预习到这儿,

通分就行了啊
(5lg3)/(6lg2)*(3lg2)/(2lg3)=5/4