若/a-1/+（b+2）^2=0,A=3a^2-6ab+b^2,B= -a^2-5,求A-B的值.

若/a-1/+（b+2）^2=0,A=3a^2-6ab+b^2,B= -a^2-5,求A-B的值.
若/a-1/+（b+2）^2=0,A=3a^2-6ab+b^2,B= -a^2-5,求A-B的值.

若/a-1/+（b+2）^2=0,A=3a^2-6ab+b^2,B= -a^2-5,求A-B的值.
由于绝对值和平方都非负,根据条件,a=1,b=-2
所以A=19,B=-6
A-B=25

/a-1/+（b+2）^2=0
===>a=1,b=-2
A=3a^2-6ab+b^2，B= -a^2-5
===>A-B=3a^2-6ab+b^2+a^2+5
=4a^2-6ab+b^2+5=4+12+4+5=25