已知x^3=10-y^3,x^2y-xy^2=-3,求代数式(x^3-y^3)-(2x^y-4xy^2)-2(-y^3+xy^2)的值

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 05:51:05
已知x^3=10-y^3,x^2y-xy^2=-3,求代数式(x^3-y^3)-(2x^y-4xy^2)-2(-y^3+xy^2)的值

已知x^3=10-y^3,x^2y-xy^2=-3,求代数式(x^3-y^3)-(2x^y-4xy^2)-2(-y^3+xy^2)的值
已知x^3=10-y^3,x^2y-xy^2=-3,求代数式(x^3-y^3)-(2x^y-4xy^2)-2(-y^3+xy^2)的值

已知x^3=10-y^3,x^2y-xy^2=-3,求代数式(x^3-y^3)-(2x^y-4xy^2)-2(-y^3+xy^2)的值
x^3=10-y^3,x^2y-xy^2=-3
则x^3+y^3=10,x^2y-xy^2=-3
(x^3-y^3)-(2x^y-4xy^2)-2(-y^3+xy^2)
=x^3-y^3-2x^y+4xy^2+2y^3-2xy^2
=x^3+y^3-2x^y+2xy^2
=(x^3+y^3)-2(x^y-xy^2)
=10+6
=16