方程2y²+3=7y配方后,得2(y-7/4)²=____.

方程2y²+3=7y配方后,得2(y-7/4)²=____.
方程2y²+3=7y配方后,得2(y-7/4)²=____.

方程2y²+3=7y配方后,得2(y-7/4)²=____.
25/8
因为 2y²+3=7y 所以 2y²-7y =—3=
2(y-7/4)²=2（y²-7y/2+49/16）=2y²-7y +49/8
=—3+49/8
=25/8

方程2y²+3=7y配方后,得2(y-7/4)²= 25/8

八分之二十五