已知1/2x-y=-3,求代数式[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]除以4x的值

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已知1/2x-y=-3,求代数式[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]除以4x的值

已知1/2x-y=-3,求代数式[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]除以4x的值
已知1/2x-y=-3,求代数式[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]除以4x的值

已知1/2x-y=-3,求代数式[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]除以4x的值
[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]÷4x
=(9x²-4y²-5x²-8xy+4y²)/4x
=(4x²-8xy)/4x
=x-2y
=2(1/2x-y)
=2×(-3)
=-6

依题意,得
[(9x^2-4y^2)-(5x^2+8xy-4y^2)]/4x=(4x^2-8xy)/4x=(x^2-2xy)/x (x≠0)=x-2y=2[(x/2)
-y]=-6
注:仅供参考!