计算,(5y+1)(5y²—5y+1)—5(1+2y)(1—2y),

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计算,(5y+1)(5y²—5y+1)—5(1+2y)(1—2y),

计算,(5y+1)(5y²—5y+1)—5(1+2y)(1—2y),
计算,(5y+1)(5y²—5y+1)—5(1+2y)(1—2y),

计算,(5y+1)(5y²—5y+1)—5(1+2y)(1—2y),
(5y+1)(5y²—5y+1)—5(1+2y)(1—2y)
=25y³-25y²+5y+5y²-5y+1-5+20y²
=25y³-4

您好!请问(5y+1)(5y²—5y+1)—5(1+2y)(1—2y)=0吗?