3sin2x+cos2x+1=2sin(2x+π/6)+1 怎么得到的2sin(2x+π/6)+1打错了，是（根号下3）sin2x+cos2x+1

3sin2x+cos2x+1=2sin(2x+π/6)+1 怎么得到的2sin(2x+π/6)+1打错了，是（根号下3）sin2x+cos2x+1
3sin2x+cos2x+1=2sin(2x+π/6)+1 怎么得到的2sin(2x+π/6)+1
打错了，是（根号下3）sin2x+cos2x+1

3sin2x+cos2x+1=2sin(2x+π/6)+1 怎么得到的2sin(2x+π/6)+1打错了，是（根号下3）sin2x+cos2x+1
化简,.
已经忘记了,