tan(x/3-π/3)=1,求x的集合

tan(x/3-π/3)=1,求x的集合
tan(x/3-π/3)=1,求x的集合

tan(x/3-π/3)=1,求x的集合
x/3-π/3 = π/4+kπ
所以,{x|x=7π/4+3kπ,k∈Z}

tan(兀/4或5兀/4）=1
所以x{5/4,19/4}

x/3-π/3=π/4+nπ
x-π=3π/4+3nπ
x=7π/4+3nπ(n=0,±1,±2,±3……)