1/(x-1)(x+1)+1/(x+1)(x+3)+1/(x+3)(x+5)+1/(x+5)(x+7)+1/(x+7)(x+9)+1/(x+9)(x+11)x=√3-5化简求值

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/04 22:22:32
1/(x-1)(x+1)+1/(x+1)(x+3)+1/(x+3)(x+5)+1/(x+5)(x+7)+1/(x+7)(x+9)+1/(x+9)(x+11)x=√3-5化简求值

1/(x-1)(x+1)+1/(x+1)(x+3)+1/(x+3)(x+5)+1/(x+5)(x+7)+1/(x+7)(x+9)+1/(x+9)(x+11)x=√3-5化简求值
1/(x-1)(x+1)+1/(x+1)(x+3)+1/(x+3)(x+5)+1/(x+5)(x+7)+1/(x+7)(x+9)+1/(x+9)(x+11)
x=√3-5
化简求值

1/(x-1)(x+1)+1/(x+1)(x+3)+1/(x+3)(x+5)+1/(x+5)(x+7)+1/(x+7)(x+9)+1/(x+9)(x+11)x=√3-5化简求值
1/(x-1)(x+1)+1/(x+1)(x+3)+1/(x+3)(x+5)+1/(x+5)(x+7)+1/(x+7)(x+9)+1/(x+9)(x+11)
=(1/2)×[1/(x-1)-1/(x+1)+1/(x+1)-1/(x+3)+1/(x+3)-1/(x+5)+1/(x+5)-1/(x+7)+1/(x+7)-1/(x+9)+1/(x+9)-1/(x+11)]
=(1/2)×(1/(x-1)-1/(x+11)]
=(1/2)×(x+11-x+1)/[(x-1)(x+11)]
=6/[(x-1)(x+11)]
=6/[(√3-6)(√3+6)]
=6/(3-36)
=-6/33
=-2/11

1/(x-1)(x+1)+1/(x+1)(x+3)+1/(x+3)(x+5)+1/(x+5)(x+7)+1/(x+7)(x+9)+1/(x+9)(x+11)
=1/2[1/(x-1)-1/(x+1)+1/(x+1)-1/(x+3)+1/(x+3)-1/(x+5)+1/(x+5)-1/(x+7)+1/(x+7)-1/(x+9)+1/(x+9)-1/(x+11)]
=1/2[1/(x-1)-1/(x+11)]
=6/(x-1)(x+11)
=6/(√3-6)(√3+6)
=6/(3-36)=-2/11