作业帮for ( ; i ^ 1; i >>= 原程序完整代码如下：# include # include # define N 100005int n,D;int cnt[4 * N],num[N];void update(int i){for ( ; i ^ 1; i >>= 1){cnt[i >> 1] = cnt[i] + cnt[i ^ 1];}}int query(int s,int t){int ret;ret = 0;s += D-1,t +=
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![for ( ; i ^ 1; i >>= 原程序完整代码如下：# include # include # define N 100005int n,D;int cnt[4 * N],num[N];void update(int i){for ( ; i ^ 1; i >>= 1){cnt[i >> 1] = cnt[i] + cnt[i ^ 1];}}int query(int s,int t){int ret;ret = 0;s += D-1,t +=](/uploads/image/z/13911636-12-6.jpg?t=for+%28+%3B+i+%5E+1%3B+i+%3E%3E%3D+%E5%8E%9F%E7%A8%8B%E5%BA%8F%E5%AE%8C%E6%95%B4%E4%BB%A3%E7%A0%81%E5%A6%82%E4%B8%8B%EF%BC%9A%23+include+%23+include+%23+define+N+100005int+n%2CD%3Bint+cnt%5B4+%2A+N%5D%2Cnum%5BN%5D%3Bvoid+update%28int+i%29%7Bfor+%28+%3B+i+%5E+1%3B+i+%3E%3E%3D+1%29%7Bcnt%5Bi+%3E%3E+1%5D+%3D+cnt%5Bi%5D+%2B+cnt%5Bi+%5E+1%5D%3B%7D%7Dint+query%28int+s%2Cint+t%29%7Bint+ret%3Bret+%3D+0%3Bs+%2B%3D+D-1%2Ct+%2B%3D)
for ( ; i ^ 1; i >>= 原程序完整代码如下：# include # include # define N 100005int n,D;int cnt[4 * N],num[N];void update(int i){for ( ; i ^ 1; i >>= 1){cnt[i >> 1] = cnt[i] + cnt[i ^ 1];}}int query(int s,int t){int ret;ret = 0;s += D-1,t +=
for ( ; i ^ 1; i >>=
原程序完整代码如下：
# include # include
# define N 100005
int n,D;int cnt[4 * N],num[N];
void update(int i)
{
for ( ; i ^ 1; i >>= 1)
{
cnt[i >> 1] = cnt[i] + cnt[i ^ 1];
}
}
int query(int s,int t)
{
int ret;
ret = 0;
s += D-1,t += D+1;
for ( ; s ^ t ^ 1; s >>= 1,t >>= 1)
{
if s & 0x1) ret += cnt[s+1];
if ( t & 0x1) ret += cnt[t-1];
}
return ret;
}
void init(void)
{
for (D = 1; D < N+2; D
for ( ; i ^ 1; i >>= 原程序完整代码如下：# include # include # define N 100005int n,D;int cnt[4 * N],num[N];void update(int i){for ( ; i ^ 1; i >>= 1){cnt[i >> 1] = cnt[i] + cnt[i ^ 1];}}int query(int s,int t){int ret;ret = 0;s += D-1,t +=
for ( ; i ^ 1; i >>= 1)
for循环,判断条件为i^1（即i的二进制最低位与1进行位异或）,i>>=1将i的二进制值右移1为再赋给i