作业帮求f(x)=4的x方-2的（x+2）方+5,x∈[1,3]的值域.
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![求f(x)=4的x方-2的（x+2）方+5,x∈[1,3]的值域.](/uploads/image/z/13305128-32-8.jpg?t=%E6%B1%82f%28x%29%3D4%E7%9A%84x%E6%96%B9-2%E7%9A%84%EF%BC%88x%2B2%EF%BC%89%E6%96%B9%2B5%2Cx%E2%88%88%5B1%2C3%5D%E7%9A%84%E5%80%BC%E5%9F%9F.)
求f(x)=4的x方-2的（x+2）方+5,x∈[1,3]的值域.
求f(x)=4的x方-2的（x+2）方+5,x∈[1,3]的值域.
求f(x)=4的x方-2的（x+2）方+5,x∈[1,3]的值域.
f(x)=(2^x)^2-2^x*4+5=(2^x-2)^2+1
又1<=x<=3,则2<=2^x<=8
0<=2^x-2<=6.
0<=(2^x-2)^2<=36
所以,1<=f(x)<=37
即值域是[1,37]