积分(-1,1)|x-1|x^2dx A,0 B,2∫下0上1(x∧2-x∧3)dx c,2∫下0积分(-1,1)|x-1|x^2dxA,0B,2∫下0上1(x∧2-x∧3)dxc,2∫下0上1(x∧2)dxd,2∫下0上1(x∧3-x∧2)dx

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积分(-1,1)|x-1|x^2dx A,0 B,2∫下0上1(x∧2-x∧3)dx c,2∫下0积分(-1,1)|x-1|x^2dxA,0B,2∫下0上1(x∧2-x∧3)dxc,2∫下0上1(x∧2)dxd,2∫下0上1(x∧3-x∧2)dx

积分(-1,1)|x-1|x^2dx A,0 B,2∫下0上1(x∧2-x∧3)dx c,2∫下0积分(-1,1)|x-1|x^2dxA,0B,2∫下0上1(x∧2-x∧3)dxc,2∫下0上1(x∧2)dxd,2∫下0上1(x∧3-x∧2)dx
积分(-1,1)|x-1|x^2dx A,0 B,2∫下0上1(x∧2-x∧3)dx c,2∫下0
积分(-1,1)|x-1|x^2dx
A,0
B,2∫下0上1(x∧2-x∧3)dx
c,2∫下0上1(x∧2)dx
d,2∫下0上1(x∧3-x∧2)dx

积分(-1,1)|x-1|x^2dx A,0 B,2∫下0上1(x∧2-x∧3)dx c,2∫下0积分(-1,1)|x-1|x^2dxA,0B,2∫下0上1(x∧2-x∧3)dxc,2∫下0上1(x∧2)dxd,2∫下0上1(x∧3-x∧2)dx
选C
I=∫(-1→1)(1-x)x^2dx
= ∫(-1→1)(x^2-x^3)dx
=2∫(0→1)x^2dx-0
=2∫(0→1)x^2dx
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B