作业帮What is the probability that if there are four people in a room,at least two of them have the same birth month?一个房间有4个人,最少2个人生日是同月的概率是多少
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What is the probability that if there are four people in a room,at least two of them have the same birth month?一个房间有4个人,最少2个人生日是同月的概率是多少
What is the probability that if there are four people in a room,at least two of them have the same birth month?
一个房间有4个人,最少2个人生日是同月的概率是多少
What is the probability that if there are four people in a room,at least two of them have the same birth month?一个房间有4个人,最少2个人生日是同月的概率是多少
这个问题可能需要在每个人的生日月份概率都是1/12的前提下进行（要不然按365天平均的概率就算死了…）
4个人的生日月份可能性有12*12*12*12=20736
最少2个人生日同月份,反面是“4个人生日在不同的4个月”,可能性有：12*11*10*9=11880
所以最少2个人生日同月份的概率是1-12*11*10*9/(12*12*12*12)=41/96
希望我的概率和算术还没有退化到一定程度= =
answer:
四个人里选两个人共4*3/(2*1)种组合
两个人生日同月的概率是1/12
则答案为：1/2
答案:The probability is that they all were born after October.
译文: 如果一个房间里面4个人里至少有两个人同一个月份出生,那么可能的情况是什么?
答案: 他们都在10月以后出生.
都在10月以后出生,那么4个人里面肯定有两个同一个月生.是数学问题.我问的是概率,不是翻译. 而且你的回答很囧.C上3下4 X ...
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答案:The probability is that they all were born after October.
译文: 如果一个房间里面4个人里至少有两个人同一个月份出生,那么可能的情况是什么?
答案: 他们都在10月以后出生.
都在10月以后出生,那么4个人里面肯定有两个同一个月生.
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