试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关

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试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关

试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关
试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关

试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关
x34x2y这中间少点什么吧?

证明:原式=x3+3x2y-4x2y+6y3-2x3+x2y+xy2+y3+1+x3-4x2y+3xy2-7y3
=1
与xy的取值无关。

试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关 试说明:无论x,y取何值时,代数式(x3+3x2y-5+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y2)的值是常数.要具体过程,注意格式 3x2y+xy2-[2xy2-4x2y+(x2y-2xy2)] 试说明:无论x,y取何值时,代数式(x3+3x2y-5xy+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3x 试说明:无论x,y取何值时,代数式(x^3+3x^2y-5xy+6y^3)+(y^3+2xy^2+x^2y-2x^3)-(4x^2y-x^3-3xy^2+7y^3)的值是常数. 因式分解:-x3-4xy2+4x2y x.y取何值时,代数(x3y+3x2y-5xy2+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y3).y取何值时,代数(x3y+3x2y-5xy2+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y3)的值都是常数? 5xy2-【3xy2-(4xy2-2x2y)】+2x2y】+2x2y-xy2 化简,再求值 已知A=x3-2y3+3x2y+xy2-3xy+4,B=y3-x3-4x2y-3xy-3xy2+3,C=y3+x2y+2xy2+6xy-6,试着说明对于x,y,z的任何值,A+B+C是常数.某同学做一道代数题:求代数式10x9+9x8+8x7+…+3x2+2x+1,当x=-1时 A=x3-2y3+3x2y-3xy+4 B=y3-x3-4x2y-3xy-3xy2+3 C=y3+x2y+2xy2+6xy-6 试说明对于x y z的任何值A+B+C是常数希望可以给我一个详细的答案, 已知X大于Y,试比较X3-X2y+XY2与X2Y-XY2+Y3的大小. (4xy2-2x2y)-( )=x3-2x2y+4xy2+y3. 因式分解:x3-y3-x2y+xy2 x3-2x2y+xy2-x 因式分解:x3-2x2y+xy2 x3+x2y-xy2-y3= 已知x>y,试比较x3-x2y+xy2与x2y-xy2+y3的大小!题中的2、3均为x、y 的2、3次方!急 若m=x3-3x2y+2xy2+3y2 n=x3-2x2y+xy2-5y3,则2x3-7x2y+5xy2+14y2等于( )若m=x3-3x2y+2xy2+3y2 n=x3-2x2y+xy2-5y3,则2x3-7x2y+5xy2+14y2等于( )空里用字母表示 若(x-3)+|y+2|=0,求代数式3x2y-【xy2减2(2xy2减3x2y)+x2y】+4xy2