试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关
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试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关
试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关
试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关
x34x2y这中间少点什么吧?
证明:原式=x3+3x2y-4x2y+6y3-2x3+x2y+xy2+y3+1+x3-4x2y+3xy2-7y3
=1
与xy的取值无关。
试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关
试说明:无论x,y取何值时,代数式(x3+3x2y-5+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y2)的值是常数.要具体过程,注意格式
3x2y+xy2-[2xy2-4x2y+(x2y-2xy2)]
试说明:无论x,y取何值时,代数式(x3+3x2y-5xy+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3x 试说明:无论x,y取何值时,代数式(x^3+3x^2y-5xy+6y^3)+(y^3+2xy^2+x^2y-2x^3)-(4x^2y-x^3-3xy^2+7y^3)的值是常数.
因式分解:-x3-4xy2+4x2y
x.y取何值时,代数(x3y+3x2y-5xy2+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y3).y取何值时,代数(x3y+3x2y-5xy2+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y3)的值都是常数?
5xy2-【3xy2-(4xy2-2x2y)】+2x2y】+2x2y-xy2 化简,再求值
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已知X大于Y,试比较X3-X2y+XY2与X2Y-XY2+Y3的大小.
(4xy2-2x2y)-( )=x3-2x2y+4xy2+y3.
因式分解:x3-y3-x2y+xy2
x3-2x2y+xy2-x
因式分解:x3-2x2y+xy2
x3+x2y-xy2-y3=
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