若sin(180°+α)=根号10/10,则【sin(-α)+sin(-90º-α)】/【cos (540º-α)+若sin(180°+α)=根号10/10,则【sin(-α)+sin(-90º-α)】/【cos (540º-α)+cos(-270º-α)】=?

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/19 00:55:32
若sin(180°+α)=根号10/10,则【sin(-α)+sin(-90º-α)】/【cos (540º-α)+若sin(180°+α)=根号10/10,则【sin(-α)+sin(-90º-α)】/【cos (540º-α)+cos(-270º-α)】=?

若sin(180°+α)=根号10/10,则【sin(-α)+sin(-90º-α)】/【cos (540º-α)+若sin(180°+α)=根号10/10,则【sin(-α)+sin(-90º-α)】/【cos (540º-α)+cos(-270º-α)】=?
若sin(180°+α)=根号10/10,则【sin(-α)+sin(-90º-α)】/【cos (540º-α)+
若sin(180°+α)=根号10/10,则【sin(-α)+sin(-90º-α)】/【cos (540º-α)+cos(-270º-α)】=?

若sin(180°+α)=根号10/10,则【sin(-α)+sin(-90º-α)】/【cos (540º-α)+若sin(180°+α)=根号10/10,则【sin(-α)+sin(-90º-α)】/【cos (540º-α)+cos(-270º-α)】=?

哪里不明白再问我.

若sin(180°+α)=根号10/10,则【sin(-α)+sin(-90º-α)】/【cos (540º-α)+若sin(180°+α)=根号10/10,则【sin(-α)+sin(-90º-α)】/【cos (540º-α)+cos(-270º-α)】=? 化简根号1-sin²(-40°)和根号1-2sinα10°cos10°/sin10°-根号1-sin²10° 若sinα=根号5/5,sinβ=根号10/10,且α与β均为锐角,则α+β= 若sinα=1/根号5,sinβ=1/根号10,α、β在0到90度之间,则α+β是(过程) α,β为钝角,sinα=根号5/5,sinβ=根号10/10,求α加β α、β为锐角.sinα=(根号5)/5,sin(α-β)=(-根号10)/10,求β 若根号2sin(x+10°)-1=0,则锐角x= 1、sinαsinβ-cosαcosβ=2、化简cos(α-β)cos(α+β)+sin(α-β)sin(α+β)=3、若α,β都是锐角,且sinα=1/根号10,cosβ=2/根号5,则cos(α+β)=4、cos75°-cos15°=5、在三角形ABC中,cosAcosB>sinAsinB,则此三角形是什么三角 已知α,β为钝角,且sinα=根号10/10,sinβ=根号5/5,则α+β= 已知sinα=根号5/5,sinβ=根号10/10,且α,β为锐角,求α+β的值 已知sinα=根号5/5,sin(α-β)=负根号10/10,α,β均为锐角,求β 已知sinα=根号5/5,sin(α-β)=-根号10/10,α,β均为锐角,则β等于多少完整的 cos(10°+α)=2分之根号3 2sin(α+15°)=根号3求锐角α的度数 若α、β均为钝角,sinα=根号5/5,cosβ=-3根号10/10,求α+β的值求具体过程. 若sinα=根号10/10,0<α<π/2,β=arccos(-根号5/5),求α+β的值 sinα+cosα=根号2/2,(90° 若sin(α-β/2)=2根号5/5,cos(α/2-β)=根号10/10,且π/2 已知α,β为锐角,sinα=根号5/5,cosβ=根号10/10,求α-β