满足不等式tan(2x+π/3)

满足不等式tan(2x+π/3)
满足不等式tan(2x+π/3)

满足不等式tan(2x+π/3)
tan(2x+π/3)≤1
所以kπ-π/2＜2x+π/3≤kπ+π/4,k∈Z
所以kπ-5π/6＜2x≤kπ-π/12,k∈Z
故kπ/2-5π/12＜x≤kπ/2-π/24,k∈Z
即x的取值范围是(kπ/2-5π/12,kπ/2-π/24],k∈Z

1/12 (12 pi n+pi)

第一三象限，tan>0,

第二四象限，tan<0,

画图：

2kπ-π/2 ≤ 2x+π/3 ≤ 2kπ+π/4

2kπ-3π/2 ≤ 2x+π/3 ≤ 2kπ-3π/4

求解他们就行了。

kπ-5π/12 ≤ x ≤ kπ-π/24

kπ-11π/12 ≤ x ≤ kπ-13π/24

其中k为整数。