已知:等差数列,满足an+an+1+an+2=4则该数列为递增数列求证明n+1,n+2是下标

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已知:等差数列,满足an+an+1+an+2=4则该数列为递增数列求证明n+1,n+2是下标

已知:等差数列,满足an+an+1+an+2=4则该数列为递增数列求证明n+1,n+2是下标
已知:等差数列,满足an+an+1+an+2=4则该数列为递增数列
求证明
n+1,n+2是下标

已知:等差数列,满足an+an+1+an+2=4则该数列为递增数列求证明n+1,n+2是下标
a(n) = a(n+3) .不可能递增.

不成立
从条件中可以得出an+1=4/3
例如an=5/3,an+2=1时,也能满足条件,但数列为递减

An+An+1+An+2=A1+An+1+A2n+1=4
无法比较A1与A2n+1的大小,无法证明

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