设f(x)在[a,b]上二阶可导

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设f(x)在[a,b]上二阶可导
设f(x)在[a,b]上二阶可导,且f''(x)>0,证明:函数F(x)=(f(x)-f(a))/(x-a)在(a,b]上单调增加

设f(x)在[a,b]上二阶可导,且f''''(x)>0,证明:函数F(x)=(f(x)-f(a))/(x-a)在(a,b]上单调增加设f(x)在[a,b]上二阶可导,且f''''(x)>0,证明:函数F(x

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设f(x)在[a,b]二阶可导,且f''''(x)设f(x)在[a,b]二阶可导,且f''''(x)设f(x)在[a,b]二阶可导,且f''''(x)这也就是所谓的Hadamard不等式得一边,条件是f是凸函数,

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