求∫1/5x+11dx

∫x^11/(1+x^4)^3dx求不定积分∫x^11/(1+x^4)^3dx求不定积分∫x^11/(1+x^4)^3dx求不定积分

求不定积分∫1/(x^2+4x+5)dx.求不定积分∫1/(x^2+4x+5)dx.求不定积分∫1/(x^2+4x+5)dx.解题关键：第二类换元积分法.满意请采纳!

求不定积分∫(1/x^2+2x+5)dx,求不定积分∫(1/x^2+2x+5)dx,求不定积分∫(1/x^2+2x+5)dx,∫1/(x^2+2x+5)dx=∫1/[(x+1)^2+4]dx=∫1/[(x+1)^2+2^2]d(x+1)=(

∫x^5/（x^4-1）dx求不定积分∫x^5/（x^4-1）dx求不定积分∫x^5/（x^4-1）dx求不定积分∫x^5/(x^4-1)dx=∫[x+x/(x^4-1)]dxletx/(x^4-1)≡A/(x-1)+B/(x+1)+(Cx

求不定积分∫5/(x-1)(2-x)dx求不定积分∫5/(x-1)(2-x)dx求不定积分∫5/(x-1)(2-x)dx

求不定积分∫(1/x^2+6x+5)dx求不定积分∫(1/x^2+6x+5)dx求不定积分∫(1/x^2+6x+5)dx∫(1/x^2+6x+5)dx=∫(1/[(x+5)(x+1)]dx=1/4∫(1/(x+1)-1/(x+5)dx=1/

求∫x/(1+x)^3dx求∫x/(1+x)^3dx求∫x/(1+x)^3dx

求∫x(x+1)^0.5dx求∫x(x+1)^0.5dx求∫x(x+1)^0.5dxa=√(x+1)x=a²-1dx=2ada所以原式=∫(a²-1)*a*2ada=∫(2a^4-2a²)da=2a^5/5+2

求积分:∫x/(1-x)dx求积分:∫x/(1-x)dx求积分:∫x/(1-x)dx

求∫x/（1-x）dx求∫x/（1-x）dx求∫x/（1-x）dx答：∫x/(1-x)dx=-∫(x-1+1)/(x-1)dx=-∫1+1/(x-1)dx=-x-ln(x-1)+CF下面有数字吧？答：∫x/(1-x)dx=-∫(x-1+1)

求∫1/（X+X）dx求∫1/（X+X）dx求∫1/（X+X）dxln绝对值x/（x+1）+c不就是求导呢，ln|x/x+1+c|

：求∫sin^2xcos^2xdx和∫x^5根号(1-x^2)dx：求∫sin^2xcos^2xdx和∫x^5根号(1-x^2)dx：求∫sin^2xcos^2xdx和∫x^5根号(1-x^2)dx∫sin²xcos²x

求不定积分,∫dx/(11+5x)^3,求不定积分,∫dx/(11+5x)^3,求不定积分,∫dx/(11+5x)^3,先配一下dx=1/5d(5x+11)∫dx/(11+5x)^3=1/5∫d(5x+11)/(11+5x)^3=-1/[1

求反常积分∫[1,5]dx/(√5-x)求反常积分∫[1,5]dx/(√5-x)求反常积分∫[1,5]dx/(√5-x)

求反常积分∫(1,5)1/(x-2)dx求反常积分∫(1,5)1/(x-2)dx求反常积分∫(1,5)1/(x-2)dx=∫(3,5)1/(x-2)dx

∫(1/³√(5-3x))dx求不定积分∫(1/³√(5-3x))dx求不定积分∫(1/³√(5-3x))dx求不定积分求不定积分∫[1/∛(5-3x)]dx原式=∫[(5-3x)^(-1/3)]d

求不定积分：∫xARCTANx/{(1+x^2)^(5/2)}dx求不定积分：∫xARCTANx/{(1+x^2)^(5/2)}dx求不定积分：∫xARCTANx/{(1+x^2)^(5/2)}dx

∫(0,1)5^x(dx)=求∫(0,1)5^x(dx)=求∫(0,1)5^x(dx)=求请稍等.

求不定积分∫（3x-1)^5dx求不定积分∫（3x-1)^5dx求不定积分∫（3x-1)^5dx.

求∫1到5（｜2-x｜+｜sinx｜）dx求∫1到5（｜2-x｜+｜sinx｜）dx求∫1到5（｜2-x｜+｜sinx｜）dx∫[1→5](|2-x|+|sinx|)dx=∫[1→5]|2-x|dx+∫[1→5]|sinx|dx=∫[1→2