已知sinxsiny=1/3,求f(x,y)=sinx-cos方y的值域

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已知sinxsiny=1/3,求f(x,y)=sinx-cos方y的值域
已知x+y=a,求sinxsiny的极值快

已知x+y=a,求sinxsiny的极值快已知x+y=a,求sinxsiny的极值快已知x+y=a,求sinxsiny的极值快y=a-x,sinxsiny=sinxsin(a-x)=sinasinxc

已知sinxsiny=1,则cos(x+y)=?

已知sinxsiny=1,则cos(x+y)=?已知sinxsiny=1,则cos(x+y)=?已知sinxsiny=1,则cos(x+y)=?∵-1≤sinx≤1,-1≤siny≤1而sinx*si

已知X-Y=A,则sinxsiny的最大值?

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已知1+cosx-siny+sinxsiny=0,1-cosx-cosy+sinxcosy+0,求sinx

已知1+cosx-siny+sinxsiny=0,1-cosx-cosy+sinxcosy+0,求sinx已知1+cosx-siny+sinxsiny=0,1-cosx-cosy+sinxcosy+0

cosxcosy+sinxsiny=1/2,sin2x+sin2y=2/3,则sin(x+y)等于多少

cosxcosy+sinxsiny=1/2,sin2x+sin2y=2/3,则sin(x+y)等于多少cosxcosy+sinxsiny=1/2,sin2x+sin2y=2/3,则sin(x+y)等于

若cosxcosy+sinxsiny=1/3,则cos(2x-2y)=

若cosxcosy+sinxsiny=1/3,则cos(2x-2y)=若cosxcosy+sinxsiny=1/3,则cos(2x-2y)=若cosxcosy+sinxsiny=1/3,则cos(2x

x+y=π/3,则sinxsiny最大值

x+y=π/3,则sinxsiny最大值x+y=π/3,则sinxsiny最大值x+y=π/3,则sinxsiny最大值x+y=π/3y=π/3-xsinxsiny=sinxsin(π/3-x)=si

sinxsiny=-1,cos(x-y)的值为

sinxsiny=-1,cos(x-y)的值为sinxsiny=-1,cos(x-y)的值为sinxsiny=-1,cos(x-y)的值为sinxsiny=-1,=>cosx=cosy=0cos(x-

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已知{1+cosx-siny+sinxsiny=0,1-cosx-cosy+sinxcosy=0,求sinx的值.

已知{1+cosx-siny+sinxsiny=0,1-cosx-cosy+sinxcosy=0,求sinx的值.已知{1+cosx-siny+sinxsiny=0,1-cosx-cosy+sinxc

证明cosXcosY+sinXsinY=cos(X-Y)

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三角函数,若cosxcosy+sinxsiny=1/2,sin2x+sin2y=2/3,则sin(x+y)=?​

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已知f(x)满足2f(x)+f(1/x)=3x,求f(x)

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已知f(x)满足2f(x)+f(-x)=-3x+1,求f(x)

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已知f(x)满足f(x)+2f(1/x)=3x,求f(x) ,

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若X--Y=π/3,则sinxsiny的最大值是多少

若X--Y=π/3,则sinxsiny的最大值是多少若X--Y=π/3,则sinxsiny的最大值是多少若X--Y=π/3,则sinxsiny的最大值是多少3/4

若sinxsiny=1,则cos(x+y)的值为

若sinxsiny=1,则cos(x+y)的值为若sinxsiny=1,则cos(x+y)的值为若sinxsiny=1,则cos(x+y)的值为你好,解答如下:因为sinxsiny=1所以sinx=1

已知f(x+1/x-1)=3f(x)-2x,求f(x)

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已知f(x)+2f(1/x)=x+2/x+3,求f(x)

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